Hours to T.U.'s (Teaching Units) to FTE% (FTEF) formula
Plug in the number of Lecture or Lab hours per week.
FTE% (FTEF) to T.U. (Teaching Units) formula
FTE * 15 =
0.75 TU
T.U. (Teaching Units) to FTE% (FTEF) formula
TU / 15 =
0.05 FTE
Non-Classroom Assignments - FTEF% (35 hour work week)
a. For the 35 Hours Base Workweek:
If Hrs = 7, determine the FTE%
FTE = Hrs / .35 = 7 / .35 = 20
b. If FTE% = 20, determine the Hrs per week
Hrs = FTE% x 35 = .20 x 35 = 7
hours
/ 0.35 =
? FTE
%FTE
* 35 =
?
Non-classroom Assignments - FTEF% (32 hour work week)
a. For the 32 Hours Base Workweek:
If Hrs = 16, determine the FTE%
FTE = Hrs / .32 = 16 / .32 = 50
b. If FTE% = 50, determine the Hrs per week
Hrs = FTE% x 32 = .50 x 32 = 16
hours
/ 0.32 =
? FTE
%FTE
* 32 =
?
Weekly Census FTES
Example:
For English 1 (Tues & Th 8:00-10am)
(28 students x 4 hours per week) = 112 WSCH
112 WSCH x 17.5 = 1,960
1960/525 = 3.73 FTES
Notes: In addition to the lecture enrolled component, you might also have a lab enrolled component. That can be calculated the same way. If the lab is one day a week from 6-9pm, than (40 students x 3 hours/wk)=120 WSCH. Than 120 WSCH x 17.5 = 2100 ans 2100/525 = FTES
5 students x 3 units = 15 WSCH
15 WSCH x 17.5 = 262.5
262.5/525 = 0.5 FTES
Students
Units
WSCH
Value
FTES
*
=
?
*17.5
=
?
/ 525 =
?
Daily Census FTES
Example:
For ESL 845 (Monday to Thursday 8:00-11:00am (9 weeks) - Fall 2005 so exclude holidays so instead of 36 meetings, it would be 35 meetings.
(32 students x 3 hour per meeting) = 96 DSCH
96 DSCH x 35 meetings = 3360
3360/525 = 6.4 FTES
Students (Resident students active on census day)
Hours per
Meeting
DSCH
Number of Meetings
Value2
FTES
Wrong Number!
*
=
?
*
=
?
/ 525 =
?
FTES per Headcount
In Spring 2007, if each student is generating .350 FTES, how many students are required to generate one FTES?
1 FTES / .350 FTES = 2.857 students are required to generate 1 FTES.
1/
FTES
=
?
Most classes are 1, 2, 3, 4, 5, or 6 nominal hours. That means in a regular semester (18 weeks), lecture hours would be 18, 36, 54, 72, 90, or 108 hours respectively. This calculator can be used to determine the hours per class
meeting for a lecture or lab in the summer. For "Total Class Meetings" enter the actual number of class meetings.
For example, in a 5 week summer session that meets Monday to Friday, it might be 25 class meetings. For a 9 week summer session meeting Monday to Thursday, it would be 36 class meetings, etc.
Lecture
Hours From Catalog
Weeks per Semester
Total Lecture Hours
Total Class Meetings
Hours Per Class Meeting
*18=
?
/
Depends on length of summer session
=
?
Lab
Hours From Catalog
Weeks per Semester
Total
Lab
Hours
Total Class Meetings
Hours Per Class Meeting
*18=
?
/
Depends on length of summer session
=
?
TARS Hours Per Class
?
Passing Time
Course Weekly Contact Hours
(in catalog)
Term Contact Hours
?
(18 x WCH)
Term Length
Clock hours per week
?
(based on term length)
Meeting days per week
(1-7 days meeting days per week)
Clock hours per meeting day
?
Passing and Breaks
?
Passing time
?
Breaks
?
Minutes of Breaks
?
Contact Minutes
?
(teaching the class, clock hrs * 50 min)
Class Clock Minutes
?
(including any breaks)
Class Clock Hours
?
(decimal)
Class Clock Hours
?
(hrs:min)
Class Clock Hours
?
(rounded to five minutes)
Class Start Time
(hh:mm)
Class End Time
?
Important note when using the calculator to schedule back-to-back classes:
If a class has more than one component that is being scheduled back-to-back, such as a lecture followed immediately by a lab, add the weekly contact hours of both components together (Lec + Lab), and use that number in the spreadsheet for Weekly Contact Hours. This will make sure the appropriate break-time and passing time is being included.
Most classes need to be scheduled 10 minutes apart (to account for passing-time, even though the class will remain in the same classroom), but some meeting patterns need to be scheduled 15-20 minutes apart.
Examples:
3.0 / 1: If you have a 3.0 contact hour course meeting once per week, it could meet from 8:00AM - 10:50AM. This will include two 10 minute breaks and 10 minutes of passing time.
3.0 / 2: If you have a 3.0 contact hour course meeting twice per week, it could meet from 8:00AM - 9:15AM. This includes NO breaks and a 15 minute passing time.
1.5 x 2: Now, if you have two 1.5 contact hour classes back-to-back (a total of 3.0 hours), one right after the other, and you separate them by 10 minutes, the first component (lecture) could get scheduled for 8:00AM - 9:15AM, and then the second (lab) from 9:25AM - 10:40AM. This does not match a 3.0 hour class, since it ends 10 minutes earlier. The printed schedule will list the class as meeting from 8:00AM - 10:40AM and the instructor will assume two 10 minutes breaks (since the student is sitting in class for over two hours), which means the student will not have enough contact hours. Therefore, in this particular case, the class component should be schedule 20 minutes apart, the first from 8:00AM to 9:15AM, then a 20 minutes separation, and the second from 9:35AM to 10:50AM. This arrangement schedules the class as if it was a single 3.0 contact hour class, with the appropriate break-time and passing-time. This type of behavior happens at half hour increments, like 1.5, 2.5, etc. By adding two back-to-back components together in the calculator, you can identify the appropriate ending time of back-to-back classes.